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14231201241281 is a prime number
BaseRepresentation
bin1100111100010111010110…
…1100011101100011000001
31212101111012212211220212212
43033011311230131203001
53331131000004210111
650133420144031505
72666112301441433
oct317056554354301
955344185756785
1014231201241281
114597467104202
12171a128602595
137c2cc547566b
14372b1832c653
1519a2bd67e98b
hexcf175b1d8c1

14231201241281 has 2 divisors, whose sum is σ = 14231201241282. Its totient is φ = 14231201241280.

The previous prime is 14231201241269. The next prime is 14231201241289. The reversal of 14231201241281 is 18214210213241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14054881032256 + 176320209025 = 3748984^2 + 419905^2 .

It is a cyclic number.

It is not a de Polignac number, because 14231201241281 - 222 = 14231197046977 is a prime.

It is a super-2 number, since 2×142312012412812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14231201241289) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115600620640 + 7115600620641.

It is an arithmetic number, because the mean of its divisors is an integer number (7115600620641).

Almost surely, 214231201241281 is an apocalyptic number.

It is an amenable number.

14231201241281 is a deficient number, since it is larger than the sum of its proper divisors (1).

14231201241281 is an equidigital number, since it uses as much as digits as its factorization.

14231201241281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 32.

The spelling of 14231201241281 in words is "fourteen trillion, two hundred thirty-one billion, two hundred one million, two hundred forty-one thousand, two hundred eighty-one".