Base | Representation |
---|---|
bin | 1100111100010111010110… |
… | …1100011101100011111111 |
3 | 1212101111012212211220222011 |
4 | 3033011311230131203333 |
5 | 3331131000004210333 |
6 | 50133420144032051 |
7 | 2666112301441552 |
oct | 317056554354377 |
9 | 55344185756864 |
10 | 14231201241343 |
11 | 4597467104259 |
12 | 171a128602627 |
13 | 7c2cc54756b8 |
14 | 372b1832c699 |
15 | 19a2bd67e9cd |
hex | cf175b1d8ff |
14231201241343 has 2 divisors, whose sum is σ = 14231201241344. Its totient is φ = 14231201241342.
The previous prime is 14231201241337. The next prime is 14231201241353. The reversal of 14231201241343 is 34314210213241.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14231201241343 - 217 = 14231201110271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14231201241353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115600620671 + 7115600620672.
It is an arithmetic number, because the mean of its divisors is an integer number (7115600620672).
Almost surely, 214231201241343 is an apocalyptic number.
14231201241343 is a deficient number, since it is larger than the sum of its proper divisors (1).
14231201241343 is an equidigital number, since it uses as much as digits as its factorization.
14231201241343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 14231201241343 its reverse (34314210213241), we get a palindrome (48545411454584).
The spelling of 14231201241343 in words is "fourteen trillion, two hundred thirty-one billion, two hundred one million, two hundred forty-one thousand, three hundred forty-three".
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