Base | Representation |
---|---|
bin | 11010100000110101… |
… | …10111101101101000 |
3 | 1100202000000101002220 |
4 | 31100122313231220 |
5 | 213122413414422 |
6 | 10312234354040 |
7 | 1012510023126 |
oct | 152032675550 |
9 | 40660011086 |
10 | 14234123112 |
11 | 6044878410 |
12 | 2912b8b920 |
13 | 145ac82a71 |
14 | 99061c916 |
15 | 58497ce5c |
hex | 3506b7b68 |
14234123112 has 128 divisors (see below), whose sum is σ = 39340339200. Its totient is φ = 4255904000.
The previous prime is 14234123003. The next prime is 14234123129. The reversal of 14234123112 is 21132143241.
It is a super-3 number, since 3×142341231123 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a nude number because it is divisible by every one of its digits.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9571633 + ... + 9573119.
It is an arithmetic number, because the mean of its divisors is an integer number (307346400).
Almost surely, 214234123112 is an apocalyptic number.
14234123112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 14234123112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19670169600).
14234123112 is an abundant number, since it is smaller than the sum of its proper divisors (25106216088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14234123112 is a wasteful number, since it uses less digits than its factorization.
14234123112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1967 (or 1963 counting only the distinct ones).
The product of its digits is 1152, while the sum is 24.
Adding to 14234123112 its reverse (21132143241), we get a palindrome (35366266353).
The spelling of 14234123112 in words is "fourteen billion, two hundred thirty-four million, one hundred twenty-three thousand, one hundred twelve".
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