Base | Representation |
---|---|
bin | 100000011001111110011011… |
… | …111101110000100010011111 |
3 | 200200122000112012221211111012 |
4 | 200121332123331300202133 |
5 | 122140042103202104442 |
6 | 1223041535024445435 |
7 | 42006624551204015 |
oct | 4031763375604237 |
9 | 620560465854435 |
10 | 142522516441247 |
11 | 41459506a82058 |
12 | 13b9999a47987b |
13 | 616aa7ac35247 |
14 | 272a1ab5768b5 |
15 | 117250ec40582 |
hex | 819f9bf7089f |
142522516441247 has 2 divisors, whose sum is σ = 142522516441248. Its totient is φ = 142522516441246.
The previous prime is 142522516441159. The next prime is 142522516441267. The reversal of 142522516441247 is 742144615225241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142522516441247 - 210 = 142522516440223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 142522516441195 and 142522516441204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142522516441267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71261258220623 + 71261258220624.
It is an arithmetic number, because the mean of its divisors is an integer number (71261258220624).
Almost surely, 2142522516441247 is an apocalyptic number.
142522516441247 is a deficient number, since it is larger than the sum of its proper divisors (1).
142522516441247 is an equidigital number, since it uses as much as digits as its factorization.
142522516441247 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4300800, while the sum is 50.
The spelling of 142522516441247 in words is "one hundred forty-two trillion, five hundred twenty-two billion, five hundred sixteen million, four hundred forty-one thousand, two hundred forty-seven".
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