143100131020 has 48 divisors (see below), whose sum is σ = 374662165248. Its totient is φ = 44602637760.

The previous prime is 143100131011. The next prime is 143100131023. The reversal of 143100131020 is 20131001341.

143100131020 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 143100130985 and 143100131003.

It is not an unprimeable number, because it can be changed into a prime (143100131023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46459542 + ... + 46462621.

It is an arithmetic number, because the mean of its divisors is an integer number (7805461776).

Almost surely, 2^143100131020 is an apocalyptic number.

143100131020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

143100131020 is an abundant number, since it is smaller than the sum of its proper divisors (231562034228).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143100131020 is a wasteful number, since it uses less digits than its factorization.

143100131020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92922190 (or 92922188 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 143100131020 its reverse (20131001341), we get a palindrome (163231132361).

The spelling of 143100131020 in words is "one hundred forty-three billion, one hundred million, one hundred thirty-one thousand, twenty".