Base | Representation |
---|---|
bin | 1101000001000001110101… |
… | …0101100111000000010001 |
3 | 1212200011000201111212212120 |
4 | 3100100131111213000101 |
5 | 3333434042221444241 |
6 | 50234310420244453 |
7 | 3004646634235041 |
oct | 320203525470021 |
9 | 55604021455776 |
10 | 14311323234321 |
11 | 4618441963483 |
12 | 1731769240729 |
13 | 7ca7239515b9 |
14 | 376959381721 |
15 | 19c40c6e9666 |
hex | d041d567011 |
14311323234321 has 8 divisors (see below), whose sum is σ = 19152700240320. Its totient is φ = 9505414192272.
The previous prime is 14311323234289. The next prime is 14311323234343. The reversal of 14311323234321 is 12343232311341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14311323234321 - 25 = 14311323234289 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14311323234391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8866990045 + ... + 8866991658.
It is an arithmetic number, because the mean of its divisors is an integer number (2394087530040).
Almost surely, 214311323234321 is an apocalyptic number.
It is an amenable number.
14311323234321 is a deficient number, since it is larger than the sum of its proper divisors (4841377005999).
14311323234321 is a wasteful number, since it uses less digits than its factorization.
14311323234321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17733981975.
The product of its digits is 31104, while the sum is 33.
Adding to 14311323234321 its reverse (12343232311341), we get a palindrome (26654555545662).
The spelling of 14311323234321 in words is "fourteen trillion, three hundred eleven billion, three hundred twenty-three million, two hundred thirty-four thousand, three hundred twenty-one".
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