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143135020001 = 431033320767
BaseRepresentation
bin1000010101001110000…
…0110001001111100001
3111200110022210101201002
42011103200301033201
54321120031120001
6145431052121345
713225006411211
oct2052340611741
9450408711632
10143135020001
1155780a95066
12238a7766255
131066122bc0c
146cdbb40241
153acb08646b
hex21538313e1

143135020001 has 4 divisors (see below), whose sum is σ = 143138383872. Its totient is φ = 143131656132.

The previous prime is 143135019977. The next prime is 143135020081. The reversal of 143135020001 is 100020531341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143135020001 - 222 = 143130825697 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (143135020081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1617281 + ... + 1703486.

It is an arithmetic number, because the mean of its divisors is an integer number (35784595968).

Almost surely, 2143135020001 is an apocalyptic number.

It is an amenable number.

143135020001 is a deficient number, since it is larger than the sum of its proper divisors (3363871).

143135020001 is an equidigital number, since it uses as much as digits as its factorization.

143135020001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3363870.

The product of its (nonzero) digits is 360, while the sum is 20.

Adding to 143135020001 its reverse (100020531341), we get a palindrome (243155551342).

The spelling of 143135020001 in words is "one hundred forty-three billion, one hundred thirty-five million, twenty thousand, one".

Divisors: 1 43103 3320767 143135020001