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14341112255521 is a prime number
BaseRepresentation
bin1101000010110000110011…
…1001101101010000100001
31212202222220202210221202001
43100230030321231100201
53334431044214134041
650300114354324001
73010053062602252
oct320541471552041
955688822727661
1014341112255521
11462a038aa5a67
1217374a1589601
138004903b716c
1437818378ab29
1519d0a2a4b131
hexd0b0ce6d421

14341112255521 has 2 divisors, whose sum is σ = 14341112255522. Its totient is φ = 14341112255520.

The previous prime is 14341112255507. The next prime is 14341112255527. The reversal of 14341112255521 is 12555221114341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14041395424225 + 299716831296 = 3747185^2 + 547464^2 .

It is a cyclic number.

It is not a de Polignac number, because 14341112255521 - 25 = 14341112255489 is a prime.

It is not a weakly prime, because it can be changed into another prime (14341112255527) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170556127760 + 7170556127761.

It is an arithmetic number, because the mean of its divisors is an integer number (7170556127761).

Almost surely, 214341112255521 is an apocalyptic number.

It is an amenable number.

14341112255521 is a deficient number, since it is larger than the sum of its proper divisors (1).

14341112255521 is an equidigital number, since it uses as much as digits as its factorization.

14341112255521 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48000, while the sum is 37.

Adding to 14341112255521 its reverse (12555221114341), we get a palindrome (26896333369862).

The spelling of 14341112255521 in words is "fourteen trillion, three hundred forty-one billion, one hundred twelve million, two hundred fifty-five thousand, five hundred twenty-one".