14404523113 has 4 divisors (see below), whose sum is σ = 15251848020. Its totient is φ = 13557198208.

The previous prime is 14404523057. The next prime is 14404523129. The reversal of 14404523113 is 31132540441.

14404523113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11713299984 + 2691223129 = 108228^2 + 51877^2 .

It is a cyclic number.

It is not a de Polignac number, because 14404523113 - 2¹³ = 14404514921 is a prime.

It is a super-2 number, since 2×14404523113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14404521113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 423662428 + ... + 423662461.

It is an arithmetic number, because the mean of its divisors is an integer number (3812962005).

Almost surely, 2^14404523113 is an apocalyptic number.

It is an amenable number.

14404523113 is a deficient number, since it is larger than the sum of its proper divisors (847324907).

14404523113 is an equidigital number, since it uses as much as digits as its factorization.

14404523113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 847324906.

The product of its (nonzero) digits is 5760, while the sum is 28.

The spelling of 14404523113 in words is "fourteen billion, four hundred four million, five hundred twenty-three thousand, one hundred thirteen".