Base | Representation |
---|---|
bin | 100000110001001110001101… |
… | …101010010100111001111011 |
3 | 200220021201220220012100002021 |
4 | 200301032031222110321323 |
5 | 122342230232100103121 |
6 | 1230303452125415311 |
7 | 42233220026025226 |
oct | 4061161552247173 |
9 | 626251826170067 |
10 | 144120004300411 |
11 | 41a14a50254997 |
12 | 141b7509a0a537 |
13 | 62555c556a9c9 |
14 | 27836343725bd |
15 | 119dd5a9eb641 |
hex | 83138da94e7b |
144120004300411 has 2 divisors, whose sum is σ = 144120004300412. Its totient is φ = 144120004300410.
The previous prime is 144120004300381. The next prime is 144120004300451. The reversal of 144120004300411 is 114003400021441.
144120004300411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144120004300411 - 225 = 144119970745979 is a prime.
It is not a weakly prime, because it can be changed into another prime (144120004300451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72060002150205 + 72060002150206.
It is an arithmetic number, because the mean of its divisors is an integer number (72060002150206).
Almost surely, 2144120004300411 is an apocalyptic number.
144120004300411 is a deficient number, since it is larger than the sum of its proper divisors (1).
144120004300411 is an equidigital number, since it uses as much as digits as its factorization.
144120004300411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 144120004300411 its reverse (114003400021441), we get a palindrome (258123404321852).
The spelling of 144120004300411 in words is "one hundred forty-four trillion, one hundred twenty billion, four million, three hundred thousand, four hundred eleven".
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