144320312444130 has 256 divisors, whose sum is σ = 398887815997440. Its totient is φ = 37105929536256.

The previous prime is 144320312444123. The next prime is 144320312444137. The reversal of 144320312444130 is 31444213023441.

144320312444130 is a `hidden beast` number, since 1 + 4 + 4 + 3 + 203 + 1 + 2 + 4 + 441 + 3 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (144320312444123) and next prime (144320312444137).

It is not an unprimeable number, because it can be changed into a prime (144320312444137) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1143765724 + ... + 1143891896.

It is an arithmetic number, because the mean of its divisors is an integer number (1558155531240).

Almost surely, 2^{144320312444130} is an apocalyptic number.

144320312444130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 144320312444130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (199443907998720).

144320312444130 is an abundant number, since it is smaller than the sum of its proper divisors (254567503553310).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

144320312444130 is a wasteful number, since it uses less digits than its factorization.

144320312444130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 127502 (or 127496 counting only the distinct ones).

The product of its (nonzero) digits is 110592, while the sum is 36.

Adding to 144320312444130 its reverse (31444213023441), we get a palindrome (175764525467571).

The spelling of 144320312444130 in words is "one hundred forty-four trillion, three hundred twenty billion, three hundred twelve million, four hundred forty-four thousand, one hundred thirty".