Base | Representation |
---|---|
bin | 1101001000100110100010… |
… | …0011101101100001101011 |
3 | 1220010120212101022212012201 |
4 | 3102021220203231201223 |
5 | 3343102024131204011 |
6 | 50414145302521031 |
7 | 3020234126446312 |
oct | 322115043554153 |
9 | 56116771285181 |
10 | 14441434241131 |
11 | 466863a161677 |
12 | 1752a1b136177 |
13 | 809a8a821821 |
14 | 37cd7d4a5279 |
15 | 1a09c5188cc1 |
hex | d22688ed86b |
14441434241131 has 2 divisors, whose sum is σ = 14441434241132. Its totient is φ = 14441434241130.
The previous prime is 14441434241111. The next prime is 14441434241219. The reversal of 14441434241131 is 13114243414441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14441434241131 - 211 = 14441434239083 is a prime.
It is a super-2 number, since 2×144414342411312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14441434241111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220717120565 + 7220717120566.
It is an arithmetic number, because the mean of its divisors is an integer number (7220717120566).
Almost surely, 214441434241131 is an apocalyptic number.
14441434241131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14441434241131 is an equidigital number, since it uses as much as digits as its factorization.
14441434241131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 73728, while the sum is 37.
Adding to 14441434241131 its reverse (13114243414441), we get a palindrome (27555677655572).
The spelling of 14441434241131 in words is "fourteen trillion, four hundred forty-one billion, four hundred thirty-four million, two hundred forty-one thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •