145200432530011 has 4 divisors (see below), whose sum is σ = 145202034443472. Its totient is φ = 145198830616552.

The previous prime is 145200432529987. The next prime is 145200432530113. The reversal of 145200432530011 is 110035234002541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145200432530011 - 2¹³ = 145200432521819 is a prime.

It is a super-2 number, since 2×145200432530011² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145200432530711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 800820760 + ... + 801002053.

It is an arithmetic number, because the mean of its divisors is an integer number (36300508610868).

Almost surely, 2^{145200432530011} is an apocalyptic number.

145200432530011 is a deficient number, since it is larger than the sum of its proper divisors (1601913461).

145200432530011 is an equidigital number, since it uses as much as digits as its factorization.

145200432530011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1601913460.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 145200432530011 its reverse (110035234002541), we get a palindrome (255235666532552).

The spelling of 145200432530011 in words is "one hundred forty-five trillion, two hundred billion, four hundred thirty-two million, five hundred thirty thousand, eleven".