14540440133 has 2 divisors, whose sum is σ = 14540440134. Its totient is φ = 14540440132.

The previous prime is 14540440091. The next prime is 14540440147. The reversal of 14540440133 is 33104404541.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8558655169 + 5981784964 = 92513^2 + 77342^2 .

It is a cyclic number.

It is not a de Polignac number, because 14540440133 - 2¹⁴ = 14540423749 is a prime.

It is a super-2 number, since 2×14540440133² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14540440096 and 14540440105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14540440183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7270220066 + 7270220067.

It is an arithmetic number, because the mean of its divisors is an integer number (7270220067).

Almost surely, 2^14540440133 is an apocalyptic number.

It is an amenable number.

14540440133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14540440133 is an equidigital number, since it uses as much as digits as its factorization.

14540440133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 14540440133 its reverse (33104404541), we get a palindrome (47644844674).

The spelling of 14540440133 in words is "fourteen billion, five hundred forty million, four hundred forty thousand, one hundred thirty-three".