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151034113 is a prime number
BaseRepresentation
bin10010000000010…
…01100100000001
3101112012022212001
421000021210001
5302131042423
622553104001
73512524456
oct1100114401
9345168761
10151034113
117828918a
12426b8001
13253a17c9
14160b782d
15d3d5cad
hex9009901

151034113 has 2 divisors, whose sum is σ = 151034114. Its totient is φ = 151034112.

The previous prime is 151034101. The next prime is 151034129. The reversal of 151034113 is 311430151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129800449 + 21233664 = 11393^2 + 4608^2 .

It is an emirp because it is prime and its reverse (311430151) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-151034113 is a prime.

It is a super-2 number, since 2×1510341132 = 45622606579393538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (151034413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75517056 + 75517057.

It is an arithmetic number, because the mean of its divisors is an integer number (75517057).

Almost surely, 2151034113 is an apocalyptic number.

It is an amenable number.

151034113 is a deficient number, since it is larger than the sum of its proper divisors (1).

151034113 is an equidigital number, since it uses as much as digits as its factorization.

151034113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 151034113 is about 12289.5936873438. The cubic root of 151034113 is about 532.5474994181.

Adding to 151034113 its reverse (311430151), we get a palindrome (462464264).

The spelling of 151034113 in words is "one hundred fifty-one million, thirty-four thousand, one hundred thirteen".