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15202043041 is a prime number
BaseRepresentation
bin11100010100001110…
…01100010010100001
31110020110022210122011
432022013030102201
5222113210334131
610552252312521
71045502143123
oct161207142241
943213283564
1015202043041
1164a117aa39
122b43172741
13158366a253
14a42db9213
155de9240b1
hex38a1cc4a1

15202043041 has 2 divisors, whose sum is σ = 15202043042. Its totient is φ = 15202043040.

The previous prime is 15202043029. The next prime is 15202043047. The reversal of 15202043041 is 14034020251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11052106641 + 4149936400 = 105129^2 + 64420^2 .

It is a cyclic number.

It is not a de Polignac number, because 15202043041 - 25 = 15202043009 is a prime.

It is a super-2 number, since 2×152020430412 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15202043047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7601021520 + 7601021521.

It is an arithmetic number, because the mean of its divisors is an integer number (7601021521).

Almost surely, 215202043041 is an apocalyptic number.

It is an amenable number.

15202043041 is a deficient number, since it is larger than the sum of its proper divisors (1).

15202043041 is an equidigital number, since it uses as much as digits as its factorization.

15202043041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 22.

Adding to 15202043041 its reverse (14034020251), we get a palindrome (29236063292).

The spelling of 15202043041 in words is "fifteen billion, two hundred two million, forty-three thousand, forty-one".