Base | Representation |
---|---|
bin | 1000111011001101001… |
… | …1010100000110110011 |
3 | 112122202222021200121201 |
4 | 2032303103110012303 |
5 | 10003011000240430 |
6 | 154234553432031 |
7 | 14035465556632 |
oct | 2166323240663 |
9 | 478688250551 |
10 | 153332040115 |
11 | 5a033a37211 |
12 | 2587270b617 |
13 | 115c799c227 |
14 | 75c810b519 |
15 | 3ec63b08ca |
hex | 23b34d41b3 |
153332040115 has 8 divisors (see below), whose sum is σ = 184001257440. Its totient is φ = 122663759232.
The previous prime is 153332040109. The next prime is 153332040167. The reversal of 153332040115 is 511040233351.
It is a happy number.
153332040115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 153332040115 - 221 = 153329942963 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 198946 + ... + 588424.
It is an arithmetic number, because the mean of its divisors is an integer number (23000157180).
Almost surely, 2153332040115 is an apocalyptic number.
153332040115 is a deficient number, since it is larger than the sum of its proper divisors (30669217325).
153332040115 is an equidigital number, since it uses as much as digits as its factorization.
153332040115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 468221.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 153332040115 its reverse (511040233351), we get a palindrome (664372273466).
The spelling of 153332040115 in words is "one hundred fifty-three billion, three hundred thirty-two million, forty thousand, one hundred fifteen".
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