Base | Representation |
---|---|
bin | 1000111011001101001… |
… | …1010100001101011101 |
3 | 112122202222021201012111 |
4 | 2032303103110031131 |
5 | 10003011000244131 |
6 | 154234553434021 |
7 | 14035465561111 |
oct | 2166323241535 |
9 | 478688251174 |
10 | 153332040541 |
11 | 5a033a37569 |
12 | 2587270b911 |
13 | 115c799c494 |
14 | 75c810b741 |
15 | 3ec63b0ab1 |
hex | 23b34d435d |
153332040541 has 4 divisors (see below), whose sum is σ = 153604389312. Its totient is φ = 153059691772.
The previous prime is 153332040517. The next prime is 153332040551. The reversal of 153332040541 is 145040233351.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 153332040541 - 25 = 153332040509 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153332040551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136173541 + ... + 136174666.
It is an arithmetic number, because the mean of its divisors is an integer number (38401097328).
Almost surely, 2153332040541 is an apocalyptic number.
It is an amenable number.
153332040541 is a deficient number, since it is larger than the sum of its proper divisors (272348771).
153332040541 is an equidigital number, since it uses as much as digits as its factorization.
153332040541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 272348770.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 153332040541 its reverse (145040233351), we get a palindrome (298372273892).
The spelling of 153332040541 in words is "one hundred fifty-three billion, three hundred thirty-two million, forty thousand, five hundred forty-one".
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