Base | Representation |
---|---|
bin | 10110010101111110111… |
… | …000010010100100111010 |
3 | 12102210012220012202000210 |
4 | 112111332320102210322 |
5 | 200124031043310132 |
6 | 3133211232411550 |
7 | 215634302513250 |
oct | 26257670224472 |
9 | 5383186182023 |
10 | 1535432010042 |
11 | 54219a382a17 |
12 | 2096b10a6bb6 |
13 | b1a37ca8718 |
14 | 5445b2b05d0 |
15 | 29e17d12bcc |
hex | 1657ee1293a |
1535432010042 has 16 divisors (see below), whose sum is σ = 3509558880192. Its totient is φ = 438694860000.
The previous prime is 1535432010041. The next prime is 1535432010059. The reversal of 1535432010042 is 2400102345351.
It is a junction number, because it is equal to n+sod(n) for n = 1535432009991 and 1535432010009.
It is not an unprimeable number, because it can be changed into a prime (1535432010041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18278952459 + ... + 18278952542.
It is an arithmetic number, because the mean of its divisors is an integer number (219347430012).
Almost surely, 21535432010042 is an apocalyptic number.
1535432010042 is an abundant number, since it is smaller than the sum of its proper divisors (1974126870150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1535432010042 is a wasteful number, since it uses less digits than its factorization.
1535432010042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36557905013.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 1535432010042 its reverse (2400102345351), we get a palindrome (3935534355393).
The spelling of 1535432010042 in words is "one trillion, five hundred thirty-five billion, four hundred thirty-two million, ten thousand, forty-two".
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