Base | Representation |
---|---|
bin | 10110011010011110010… |
… | …000100111111101110101 |
3 | 12110020122220121021101211 |
4 | 112122132100213331311 |
5 | 200213414340400401 |
6 | 3135325504521421 |
7 | 216164626210642 |
oct | 26323620477565 |
9 | 5406586537354 |
10 | 1540253450101 |
11 | 544243a11223 |
12 | 20a617920271 |
13 | b2325b48a32 |
14 | 54797770dc9 |
15 | 2a0eb247951 |
hex | 1669e427f75 |
1540253450101 has 4 divisors (see below), whose sum is σ = 1540258138432. Its totient is φ = 1540248761772.
The previous prime is 1540253450093. The next prime is 1540253450117. The reversal of 1540253450101 is 1010543520451.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1540253450101 - 23 = 1540253450093 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1540253450191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1810941 + ... + 2521906.
It is an arithmetic number, because the mean of its divisors is an integer number (385064534608).
Almost surely, 21540253450101 is an apocalyptic number.
It is an amenable number.
1540253450101 is a deficient number, since it is larger than the sum of its proper divisors (4688331).
1540253450101 is an equidigital number, since it uses as much as digits as its factorization.
1540253450101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4688330.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 1540253450101 its reverse (1010543520451), we get a palindrome (2550796970552).
The spelling of 1540253450101 in words is "one trillion, five hundred forty billion, two hundred fifty-three million, four hundred fifty thousand, one hundred one".
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