Base | Representation |
---|---|
bin | 10110100011101011001… |
… | …101001110101000010011 |
3 | 12111012011112020111100020 |
4 | 112203223031032220103 |
5 | 200344133342340430 |
6 | 3144042154354523 |
7 | 216664526326314 |
oct | 26435315165023 |
9 | 5435145214306 |
10 | 1550134340115 |
11 | 548454472129 |
12 | 210514a2ba43 |
13 | b323bc6140a |
14 | 55053b6a60b |
15 | 2a4c8928b10 |
hex | 168eb34ea13 |
1550134340115 has 8 divisors (see below), whose sum is σ = 2480214944208. Its totient is φ = 826738314720.
The previous prime is 1550134340101. The next prime is 1550134340123. The reversal of 1550134340115 is 5110434310551.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1550134340115 - 27 = 1550134339987 is a prime.
It is a super-4 number, since 4×15501343401154 (a number of 50 digits) contains 4444 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51671144656 + ... + 51671144685.
It is an arithmetic number, because the mean of its divisors is an integer number (310026868026).
Almost surely, 21550134340115 is an apocalyptic number.
1550134340115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1550134340115 is a deficient number, since it is larger than the sum of its proper divisors (930080604093).
1550134340115 is a wasteful number, since it uses less digits than its factorization.
1550134340115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103342289349.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 1550134340115 its reverse (5110434310551), we get a palindrome (6660568650666).
The spelling of 1550134340115 in words is "one trillion, five hundred fifty billion, one hundred thirty-four million, three hundred forty thousand, one hundred fifteen".
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