Base | Representation |
---|---|
bin | 100101000100110000010111… |
… | …100111101110000000101111 |
3 | 210101022212020212122210122201 |
4 | 211010300113213232000233 |
5 | 132332441141341312031 |
6 | 1334442115200522331 |
7 | 46226205242020426 |
oct | 4504602747560057 |
9 | 711285225583581 |
10 | 163054534713391 |
11 | 47a55049028322 |
12 | 163550899203a7 |
13 | 6cc9c90902cb9 |
14 | 2c39c4b1162bd |
15 | 13cb651604d61 |
hex | 944c179ee02f |
163054534713391 has 2 divisors, whose sum is σ = 163054534713392. Its totient is φ = 163054534713390.
The previous prime is 163054534713307. The next prime is 163054534713479. The reversal of 163054534713391 is 193317435450361.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 163054534713391 - 215 = 163054534680623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (163054534713491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81527267356695 + 81527267356696.
It is an arithmetic number, because the mean of its divisors is an integer number (81527267356696).
Almost surely, 2163054534713391 is an apocalyptic number.
163054534713391 is a deficient number, since it is larger than the sum of its proper divisors (1).
163054534713391 is an equidigital number, since it uses as much as digits as its factorization.
163054534713391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12247200, while the sum is 55.
The spelling of 163054534713391 in words is "one hundred sixty-three trillion, fifty-four billion, five hundred thirty-four million, seven hundred thirteen thousand, three hundred ninety-one".
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