Base | Representation |
---|---|
bin | 1001110011101110000… |
… | …0100111100110101001 |
3 | 121002221012111011021212 |
4 | 2130323200213212221 |
5 | 10230043021143423 |
6 | 205224145242505 |
7 | 15113432324321 |
oct | 2347340474651 |
9 | 532835434255 |
10 | 168502131113 |
11 | 655090730a8 |
12 | 287a7033435 |
13 | 12b7482cb34 |
14 | 8226b6a281 |
15 | 45b30c2578 |
hex | 273b8279a9 |
168502131113 has 2 divisors, whose sum is σ = 168502131114. Its totient is φ = 168502131112.
The previous prime is 168502131101. The next prime is 168502131137. The reversal of 168502131113 is 311131205861.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 167585434384 + 916696729 = 409372^2 + 30277^2 .
It is a cyclic number.
It is not a de Polignac number, because 168502131113 - 216 = 168502065577 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 168502131113.
It is not a weakly prime, because it can be changed into another prime (168502131143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84251065556 + 84251065557.
It is an arithmetic number, because the mean of its divisors is an integer number (84251065557).
Almost surely, 2168502131113 is an apocalyptic number.
It is an amenable number.
168502131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
168502131113 is an equidigital number, since it uses as much as digits as its factorization.
168502131113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 32.
Adding to 168502131113 its reverse (311131205861), we get a palindrome (479633336974).
The spelling of 168502131113 in words is "one hundred sixty-eight billion, five hundred two million, one hundred thirty-one thousand, one hundred thirteen".
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