Base | Representation |
---|---|
bin | 110011000000001… |
… | …1111010000001001 |
3 | 11102021022022222212 |
4 | 1212000133100021 |
5 | 12001104412131 |
6 | 441453154505 |
7 | 60260460104 |
oct | 14600372011 |
9 | 4367268885 |
10 | 1711404041 |
11 | 7a9052206 |
12 | 3b918ba35 |
13 | 213740219 |
14 | 12341373b |
15 | a03a7a2b |
hex | 6601f409 |
1711404041 has 2 divisors, whose sum is σ = 1711404042. Its totient is φ = 1711404040.
The previous prime is 1711403989. The next prime is 1711404049. The reversal of 1711404041 is 1404041171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1082146816 + 629257225 = 32896^2 + 25085^2 .
It is a cyclic number.
It is not a de Polignac number, because 1711404041 - 222 = 1707209737 is a prime.
It is a super-2 number, since 2×17114040412 = 5857807583102259362, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1711403998 and 1711404016.
It is not a weakly prime, because it can be changed into another prime (1711404049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 855702020 + 855702021.
It is an arithmetic number, because the mean of its divisors is an integer number (855702021).
Almost surely, 21711404041 is an apocalyptic number.
It is an amenable number.
1711404041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1711404041 is an equidigital number, since it uses as much as digits as its factorization.
1711404041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 23.
The square root of 1711404041 is about 41369.1194129147. The cubic root of 1711404041 is about 1196.1459781718.
The spelling of 1711404041 in words is "one billion, seven hundred eleven million, four hundred four thousand, forty-one".
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