Base | Representation |
---|---|
bin | 11111111011111110… |
… | …01101001000101101 |
3 | 1122020221102110020021 |
4 | 33331333031020231 |
5 | 240103400401123 |
6 | 11513220322141 |
7 | 1144616333302 |
oct | 177577151055 |
9 | 48227373207 |
10 | 17146106413 |
11 | 72a9591587 |
12 | 33a6243351 |
13 | 180335acc7 |
14 | b892730a9 |
15 | 6a5437c5d |
hex | 3fdfcd22d |
17146106413 has 2 divisors, whose sum is σ = 17146106414. Its totient is φ = 17146106412.
The previous prime is 17146106389. The next prime is 17146106429. The reversal of 17146106413 is 31460164171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16384512004 + 761594409 = 128002^2 + 27597^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-17146106413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17146106513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8573053206 + 8573053207.
It is an arithmetic number, because the mean of its divisors is an integer number (8573053207).
Almost surely, 217146106413 is an apocalyptic number.
It is an amenable number.
17146106413 is a deficient number, since it is larger than the sum of its proper divisors (1).
17146106413 is an equidigital number, since it uses as much as digits as its factorization.
17146106413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 34.
The spelling of 17146106413 in words is "seventeen billion, one hundred forty-six million, one hundred six thousand, four hundred thirteen".
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