Base | Representation |
---|---|
bin | 10001000000100111… |
… | …010111100111001101 |
3 | 1202010211210211202112 |
4 | 101000213113213031 |
5 | 244401031300331 |
6 | 12220151233405 |
7 | 1214411566145 |
oct | 210047274715 |
9 | 52124724675 |
10 | 18263931341 |
11 | 7822570a37 |
12 | 3658678865 |
13 | 1950b10086 |
14 | c538d1925 |
15 | 71d64032b |
hex | 4409d79cd |
18263931341 has 4 divisors (see below), whose sum is σ = 18407741952. Its totient is φ = 18120120732.
The previous prime is 18263931337. The next prime is 18263931349. The reversal of 18263931341 is 14313936281.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14313936281 = 50119 ⋅285599.
It is not a de Polignac number, because 18263931341 - 22 = 18263931337 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (18263931349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71905115 + ... + 71905368.
It is an arithmetic number, because the mean of its divisors is an integer number (4601935488).
Almost surely, 218263931341 is an apocalyptic number.
It is an amenable number.
18263931341 is a deficient number, since it is larger than the sum of its proper divisors (143810611).
18263931341 is a wasteful number, since it uses less digits than its factorization.
18263931341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 143810610.
The product of its digits is 93312, while the sum is 41.
The spelling of 18263931341 in words is "eighteen billion, two hundred sixty-three million, nine hundred thirty-one thousand, three hundred forty-one".
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