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199999903 is a prime number
BaseRepresentation
bin10111110101111…
…00000110011111
3111221100001021211
423322330012133
5402144444103
631502405251
74645654045
oct1372740637
9457301254
10199999903
11a2992984
1256b90827
133258724c
141c7c2395
151285936d
hexbebc19f

199999903 has 2 divisors, whose sum is σ = 199999904. Its totient is φ = 199999902.

The previous prime is 199999901. The next prime is 199999931. The reversal of 199999903 is 309999991.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 199999903 - 21 = 199999901 is a prime.

It is a super-2 number, since 2×1999999032 = 79999922400018818, which contains 22 as substring.

Together with 199999901, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (199999901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99999951 + 99999952.

It is an arithmetic number, because the mean of its divisors is an integer number (99999952).

Almost surely, 2199999903 is an apocalyptic number.

199999903 is a deficient number, since it is larger than the sum of its proper divisors (1).

199999903 is an equidigital number, since it uses as much as digits as its factorization.

199999903 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1594323, while the sum is 58.

The square root of 199999903 is about 14142.1321942626. The cubic root of 199999903 is about 584.8034530993.

The spelling of 199999903 in words is "one hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred three".