200000000041 has 2 divisors, whose sum is σ = 200000000042. Its totient is φ = 200000000040.

The previous prime is 199999999949. The next prime is 200000000077. The reversal of 200000000041 is 140000000002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 193107513600 + 6892486441 = 439440^2 + 83021^2 .

It is a cyclic number.

It is not a de Polignac number, because 200000000041 - 2¹¹ = 199999997993 is a prime.

200000000041 is a modest number, since divided by 41 gives 20 as remainder.

It is a junction number, because it is equal to n+sod(n) for n = 199999999952 and 200000000033.

It is not a weakly prime, because it can be changed into another prime (200000000341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100000000020 + 100000000021.

It is an arithmetic number, because the mean of its divisors is an integer number (100000000021).

Almost surely, 2^200000000041 is an apocalyptic number.

It is an amenable number.

200000000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

200000000041 is an equidigital number, since it uses as much as digits as its factorization.

200000000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 7.

Adding to 200000000041 its reverse (140000000002), we get a palindrome (340000000043).

The spelling of 200000000041 in words is "two hundred billion, forty-one", and thus it is an aban number.