Base | Representation |
---|---|
bin | 10010101000110000… |
… | …101111101110000111 |
3 | 1220122121122021222122 |
4 | 102220300233232013 |
5 | 311440333013342 |
6 | 13105405520155 |
7 | 1305616363553 |
oct | 225060575607 |
9 | 56577567878 |
10 | 20011219847 |
11 | 85398a2723 |
12 | 3a6587305b |
13 | 1b6bb057b8 |
14 | d7b9a6863 |
15 | 7c1c354d2 |
hex | 4a8c2fb87 |
20011219847 has 2 divisors, whose sum is σ = 20011219848. Its totient is φ = 20011219846.
The previous prime is 20011219831. The next prime is 20011219849. The reversal of 20011219847 is 74891211002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20011219847 - 24 = 20011219831 is a prime.
Together with 20011219849, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20011219849) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005609923 + 10005609924.
It is an arithmetic number, because the mean of its divisors is an integer number (10005609924).
Almost surely, 220011219847 is an apocalyptic number.
20011219847 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011219847 is an equidigital number, since it uses as much as digits as its factorization.
20011219847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 35.
The spelling of 20011219847 in words is "twenty billion, eleven million, two hundred nineteen thousand, eight hundred forty-seven".
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