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20011220113 is a prime number
BaseRepresentation
bin10010101000110000…
…101111110010010001
31220122121122022100111
4102220300233302101
5311440333020423
613105405521321
71305616364413
oct225060576221
956577568314
1020011220113
1185398a2945
123a65873241
131b6bb05961
14d7b9a69b3
157c1c3560d
hex4a8c2fc91

20011220113 has 2 divisors, whose sum is σ = 20011220114. Its totient is φ = 20011220112.

The previous prime is 20011220093. The next prime is 20011220153. The reversal of 20011220113 is 31102211002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19939699264 + 71520849 = 141208^2 + 8457^2 .

It is a cyclic number.

It is not a de Polignac number, because 20011220113 - 217 = 20011089041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20011220093 and 20011220102.

It is not a weakly prime, because it can be changed into another prime (20011220153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005610056 + 10005610057.

It is an arithmetic number, because the mean of its divisors is an integer number (10005610057).

Almost surely, 220011220113 is an apocalyptic number.

It is an amenable number.

20011220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20011220113 is an equidigital number, since it uses as much as digits as its factorization.

20011220113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20011220113 its reverse (31102211002), we get a palindrome (51113431115).

The spelling of 20011220113 in words is "twenty billion, eleven million, two hundred twenty thousand, one hundred thirteen".