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20011220153 is a prime number
BaseRepresentation
bin10010101000110000…
…101111110010111001
31220122121122022101222
4102220300233302321
5311440333021103
613105405521425
71305616364501
oct225060576271
956577568358
1020011220153
1185398a2981
123a65873275
131b6bb05992
14d7b9a6a01
157c1c35638
hex4a8c2fcb9

20011220153 has 2 divisors, whose sum is σ = 20011220154. Its totient is φ = 20011220152.

The previous prime is 20011220113. The next prime is 20011220167. The reversal of 20011220153 is 35102211002.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18308254864 + 1702965289 = 135308^2 + 41267^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20011220153 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (20011220113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005610076 + 10005610077.

It is an arithmetic number, because the mean of its divisors is an integer number (10005610077).

Almost surely, 220011220153 is an apocalyptic number.

It is an amenable number.

20011220153 is a deficient number, since it is larger than the sum of its proper divisors (1).

20011220153 is an equidigital number, since it uses as much as digits as its factorization.

20011220153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 20011220153 its reverse (35102211002), we get a palindrome (55113431155).

The spelling of 20011220153 in words is "twenty billion, eleven million, two hundred twenty thousand, one hundred fifty-three".