Base | Representation |
---|---|
bin | 11101000111111101011… |
… | …100111110011101000011 |
3 | 21002022222211211002221010 |
4 | 131013331130332131003 |
5 | 230242342434233011 |
6 | 4131234101332003 |
7 | 264411566340342 |
oct | 35077534763503 |
9 | 7068884732833 |
10 | 2001412024131 |
11 | 701880a02483 |
12 | 283a78a07003 |
13 | 116969c62b00 |
14 | 6cc24211b59 |
15 | 370dbe4a1a6 |
hex | 1d1fd73e743 |
2001412024131 has 12 divisors (see below), whose sum is σ = 2889612627288. Its totient is φ = 1231638168384.
The previous prime is 2001412024109. The next prime is 2001412024159. The reversal of 2001412024131 is 1314202141002.
It is not a de Polignac number, because 2001412024131 - 211 = 2001412022083 is a prime.
It is a super-2 number, since 2×20014120241312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2001412024098 and 2001412024107.
It is not an unprimeable number, because it can be changed into a prime (2001412024181) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1973778610 + ... + 1973779623.
It is an arithmetic number, because the mean of its divisors is an integer number (240801052274).
Almost surely, 22001412024131 is an apocalyptic number.
2001412024131 is a deficient number, since it is larger than the sum of its proper divisors (888200603157).
2001412024131 is a wasteful number, since it uses less digits than its factorization.
2001412024131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3947558262 (or 3947558249 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 2001412024131 its reverse (1314202141002), we get a palindrome (3315614165133).
The spelling of 2001412024131 in words is "two trillion, one billion, four hundred twelve million, twenty-four thousand, one hundred thirty-one".
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