200211011011111 has 4 divisors (see below), whose sum is σ = 200304002657952. Its totient is φ = 200118019364272.

The previous prime is 200211011011009. The next prime is 200211011011153. The reversal of 200211011011111 is 111110110112002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200211011011111 - 2³³ = 200202421076519 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200211011011091 and 200211011011100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200211011014111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46495820191 + ... + 46495824496.

It is an arithmetic number, because the mean of its divisors is an integer number (50076000664488).

Almost surely, 2^{200211011011111} is an apocalyptic number.

200211011011111 is a deficient number, since it is larger than the sum of its proper divisors (92991646841).

200211011011111 is an equidigital number, since it uses as much as digits as its factorization.

200211011011111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92991646840.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 200211011011111 its reverse (111110110112002), we get a palindrome (311321121123113).

The spelling of 200211011011111 in words is "two hundred trillion, two hundred eleven billion, eleven million, eleven thousand, one hundred eleven".