Base | Representation |
---|---|
bin | 111011101010101… |
… | …1110110101110011 |
3 | 12011112100020101111 |
4 | 1313111132311303 |
5 | 13100020320201 |
6 | 530400214151 |
7 | 100420511461 |
oct | 16725366563 |
9 | 5145306344 |
10 | 2002120051 |
11 | 938165478 |
12 | 47a60a357 |
13 | 25ba3a329 |
14 | 14dc8b831 |
15 | bab80b51 |
hex | 7755ed73 |
2002120051 has 2 divisors, whose sum is σ = 2002120052. Its totient is φ = 2002120050.
The previous prime is 2002120013. The next prime is 2002120069. The reversal of 2002120051 is 1500212002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2002120051 - 211 = 2002118003 is a prime.
It is not a weakly prime, because it can be changed into another prime (2002120751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001060025 + 1001060026.
It is an arithmetic number, because the mean of its divisors is an integer number (1001060026).
Almost surely, 22002120051 is an apocalyptic number.
2002120051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002120051 is an equidigital number, since it uses as much as digits as its factorization.
2002120051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 13.
The square root of 2002120051 is about 44745.0561626645. The cubic root of 2002120051 is about 1260.3660754994.
Adding to 2002120051 its reverse (1500212002), we get a palindrome (3502332053).
The spelling of 2002120051 in words is "two billion, two million, one hundred twenty thousand, fifty-one".
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