Base | Representation |
---|---|
bin | 101101100001011111010001… |
… | …011011011001011001011100 |
3 | 222020220012211001221210121220 |
4 | 231201133101123121121130 |
5 | 202220244033003414400 |
6 | 1545452434522453340 |
7 | 60112641021402240 |
oct | 5541372133313134 |
9 | 866805731853556 |
10 | 200213414123100 |
11 | 588810397a07a4 |
12 | 1a55684b364250 |
13 | 87940756c77b1 |
14 | 3762549470420 |
15 | 1823024eb87a0 |
hex | b617d16d965c |
200213414123100 has 576 divisors, whose sum is σ = 705621617326080. Its totient is φ = 42786400665600.
The previous prime is 200213414123089. The next prime is 200213414123119. The reversal of 200213414123100 is 1321414312002.
It is a super-2 number, since 2×2002134141231002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 10379658256 + ... + 10379677544.
It is an arithmetic number, because the mean of its divisors is an integer number (1225037530080).
Almost surely, 2200213414123100 is an apocalyptic number.
200213414123100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 200213414123100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (352810808663040).
200213414123100 is an abundant number, since it is smaller than the sum of its proper divisors (505408203202980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200213414123100 is a wasteful number, since it uses less digits than its factorization.
200213414123100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21238 (or 21231 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 200213414123100 its reverse (1321414312002), we get a palindrome (201534828435102).
The spelling of 200213414123100 in words is "two hundred trillion, two hundred thirteen billion, four hundred fourteen million, one hundred twenty-three thousand, one hundred".
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