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200241124451 = 293683416807
BaseRepresentation
bin1011101001111101001…
…1010001010001100011
3201010212011000002001122
42322133103101101203
511240043211440301
6231553422122455
720316106321514
oct2723723212143
9633764002048
10200241124451
1177a15992605
123298442042b
1315b62274a74
14999812aa0b
15531e70381b
hex2e9f4d1463

200241124451 has 4 divisors (see below), whose sum is σ = 200924541552. Its totient is φ = 199557707352.

The previous prime is 200241124337. The next prime is 200241124463. The reversal of 200241124451 is 154421142002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200241124451 - 222 = 200236930147 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200241124451.

It is not an unprimeable number, because it can be changed into a prime (200241124651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341708111 + ... + 341708696.

It is an arithmetic number, because the mean of its divisors is an integer number (50231135388).

Almost surely, 2200241124451 is an apocalyptic number.

200241124451 is a deficient number, since it is larger than the sum of its proper divisors (683417101).

200241124451 is an equidigital number, since it uses as much as digits as its factorization.

200241124451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 683417100.

The product of its (nonzero) digits is 2560, while the sum is 26.

Adding to 200241124451 its reverse (154421142002), we get a palindrome (354662266453).

The spelling of 200241124451 in words is "two hundred billion, two hundred forty-one million, one hundred twenty-four thousand, four hundred fifty-one".

Divisors: 1 293 683416807 200241124451