Base | Representation |
---|---|
bin | 111011101100110… |
… | …0110110101111001 |
3 | 12011121101011201111 |
4 | 1313121212311321 |
5 | 13100304421101 |
6 | 530435320321 |
7 | 100432634215 |
oct | 16731466571 |
9 | 5147334644 |
10 | 2003201401 |
11 | 938833953 |
12 | 47aa500a1 |
13 | 25c028596 |
14 | 15008d945 |
15 | bace6251 |
hex | 77666d79 |
2003201401 has 2 divisors, whose sum is σ = 2003201402. Its totient is φ = 2003201400.
The previous prime is 2003201393. The next prime is 2003201437. The reversal of 2003201401 is 1041023002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1990944400 + 12257001 = 44620^2 + 3501^2 .
It is a cyclic number.
It is not a de Polignac number, because 2003201401 - 23 = 2003201393 is a prime.
It is not a weakly prime, because it can be changed into another prime (2003201441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001600700 + 1001600701.
It is an arithmetic number, because the mean of its divisors is an integer number (1001600701).
Almost surely, 22003201401 is an apocalyptic number.
It is an amenable number.
2003201401 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003201401 is an equidigital number, since it uses as much as digits as its factorization.
2003201401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
The square root of 2003201401 is about 44757.1379893755. The cubic root of 2003201401 is about 1260.5929436069.
Adding to 2003201401 its reverse (1041023002), we get a palindrome (3044224403).
The spelling of 2003201401 in words is "two billion, three million, two hundred one thousand, four hundred one".
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