Base | Representation |
---|---|
bin | 100110001101… |
… | …1001000110111 |
3 | 1101200211121211 |
4 | 1030123020313 |
5 | 20112042403 |
6 | 1553222251 |
7 | 332200315 |
oct | 114331067 |
9 | 41624554 |
10 | 20034103 |
11 | 10343a11 |
12 | 6861987 |
13 | 41c5acb |
14 | 29370b5 |
15 | 1b5b06d |
hex | 131b237 |
20034103 has 2 divisors, whose sum is σ = 20034104. Its totient is φ = 20034102.
The previous prime is 20034073. The next prime is 20034107. The reversal of 20034103 is 30143002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20034103 - 25 = 20034071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20034107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017051 + 10017052.
It is an arithmetic number, because the mean of its divisors is an integer number (10017052).
Almost surely, 220034103 is an apocalyptic number.
20034103 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034103 is an equidigital number, since it uses as much as digits as its factorization.
20034103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 13.
The square root of 20034103 is about 4475.9471623334. The cubic root of 20034103 is about 271.5959570239.
Adding to 20034103 its reverse (30143002), we get a palindrome (50177105).
The spelling of 20034103 in words is "twenty million, thirty-four thousand, one hundred three".
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