Base | Representation |
---|---|
bin | 10010101010001100… |
… | …001111010100110001 |
3 | 1220201021202211121110 |
4 | 102222030033110301 |
5 | 312013003020101 |
6 | 13112023543533 |
7 | 1306330266432 |
oct | 225214172461 |
9 | 56637684543 |
10 | 20035204401 |
11 | 8551394673 |
12 | 3a718baba9 |
13 | 1b73a82744 |
14 | d80c4b489 |
15 | 7c3dc1cd6 |
hex | 4aa30f531 |
20035204401 has 4 divisors (see below), whose sum is σ = 26713605872. Its totient is φ = 13356802932.
The previous prime is 20035204363. The next prime is 20035204421. The reversal of 20035204401 is 10440253002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 20035204401 - 233 = 11445269809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20035204421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3339200731 + ... + 3339200736.
It is an arithmetic number, because the mean of its divisors is an integer number (6678401468).
Almost surely, 220035204401 is an apocalyptic number.
It is an amenable number.
20035204401 is a deficient number, since it is larger than the sum of its proper divisors (6678401471).
20035204401 is an equidigital number, since it uses as much as digits as its factorization.
20035204401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6678401470.
The product of its (nonzero) digits is 960, while the sum is 21.
Adding to 20035204401 its reverse (10440253002), we get a palindrome (30475457403).
The spelling of 20035204401 in words is "twenty billion, thirty-five million, two hundred four thousand, four hundred one".
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