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BaseRepresentation
bin1001001001100100110011…
…11110000111010001101111
32122020110210000210210102112
410210302121332013101233
510114122142230324442
6110443032531514235
74144431363165653
oct444623176072157
978213700723375
1020120210011247
116457a2a022775
12230b52175897b
13b2c434b4c0c8
144d7b75430a63
1524d58d4c2082
hex124c99f8746f

20120210011247 has 2 divisors, whose sum is σ = 20120210011248. Its totient is φ = 20120210011246.

The previous prime is 20120210011159. The next prime is 20120210011249. The reversal of 20120210011247 is 74211001202102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20120210011247 - 210 = 20120210010223 is a prime.

Together with 20120210011249, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20120210011249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060105005623 + 10060105005624.

It is an arithmetic number, because the mean of its divisors is an integer number (10060105005624).

Almost surely, 220120210011247 is an apocalyptic number.

20120210011247 is a deficient number, since it is larger than the sum of its proper divisors (1).

20120210011247 is an equidigital number, since it uses as much as digits as its factorization.

20120210011247 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 448, while the sum is 23.

Adding to 20120210011247 its reverse (74211001202102), we get a palindrome (94331211213349).

The spelling of 20120210011247 in words is "twenty trillion, one hundred twenty billion, two hundred ten million, eleven thousand, two hundred forty-seven".