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20130110000 = 2454711132011
BaseRepresentation
bin10010101111110110…
…010001101000110000
31220221220100112121122
4102233312101220300
5312211302010000
613125254041412
71311562053230
oct225766215060
956856315548
1020130110000
11859aa16650
123a99649268
131b8a6314c0
14d8d6b3cc0
157cc3bc085
hex4afd91a30

20130110000 has 400 divisors, whose sum is σ = 65469643008. Its totient is φ = 5788800000.

The previous prime is 20130109939. The next prime is 20130110009. The reversal of 20130110000 is 1103102.

It is a tau number, because it is divible by the number of its divisors (400).

It is a super-2 number, since 2×201301100002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a self number, because there is not a number n which added to its sum of digits gives 20130110000.

It is not an unprimeable number, because it can be changed into a prime (20130110009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 10008995 + ... + 10011005.

Almost surely, 220130110000 is an apocalyptic number.

20130110000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20130110000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (32734821504).

20130110000 is an abundant number, since it is smaller than the sum of its proper divisors (45339533008).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20130110000 is a wasteful number, since it uses less digits than its factorization.

20130110000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2070 (or 2049 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 20130110000 its reverse (1103102), we get a palindrome (20131213102).

The spelling of 20130110000 in words is "twenty billion, one hundred thirty million, one hundred ten thousand".