Base | Representation |
---|---|
bin | 1001001001110111011010… |
… | …11110110000011100100001 |
3 | 2122021102120022122012220111 |
4 | 10210323231132300130201 |
5 | 10114303122424341001 |
6 | 110451404153411321 |
7 | 4145234101250023 |
oct | 444735536603441 |
9 | 78242508565814 |
10 | 20130201012001 |
11 | 6461196750493 |
12 | 231144b709b41 |
13 | b30367a08382 |
14 | 4d84422d0013 |
15 | 24d9756a3851 |
hex | 124eed7b0721 |
20130201012001 has 2 divisors, whose sum is σ = 20130201012002. Its totient is φ = 20130201012000.
The previous prime is 20130201011971. The next prime is 20130201012023. The reversal of 20130201012001 is 10021010203102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15697285520400 + 4432915491601 = 3961980^2 + 2105449^2 .
It is a cyclic number.
It is not a de Polignac number, because 20130201012001 - 25 = 20130201011969 is a prime.
It is not a weakly prime, because it can be changed into another prime (20130201012301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065100506000 + 10065100506001.
It is an arithmetic number, because the mean of its divisors is an integer number (10065100506001).
Almost surely, 220130201012001 is an apocalyptic number.
It is an amenable number.
20130201012001 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130201012001 is an equidigital number, since it uses as much as digits as its factorization.
20130201012001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 20130201012001 its reverse (10021010203102), we get a palindrome (30151211215103).
The spelling of 20130201012001 in words is "twenty trillion, one hundred thirty billion, two hundred one million, twelve thousand, one".
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