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20130402232131 = 36710134077377
BaseRepresentation
bin1001001001110111110010…
…11110010110011101000011
32122021110002100021021000220
410210323321132112131003
510114304030432412011
6110451440142314123
74145242063505442
oct444737136263503
978243070237026
1020130402232131
11646128a297114
1223114a6b88943
13b3039a5cbb39
144d8460d0cd59
1524d98819e506
hex124ef9796743

20130402232131 has 4 divisors (see below), whose sum is σ = 26840536309512. Its totient is φ = 13420268154752.

The previous prime is 20130402232069. The next prime is 20130402232147. The reversal of 20130402232131 is 13123220403102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20130402232131 - 215 = 20130402199363 is a prime.

It is a super-2 number, since 2×201304022321312 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (20130402252131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355067038686 + ... + 3355067038691.

It is an arithmetic number, because the mean of its divisors is an integer number (6710134077378).

Almost surely, 220130402232131 is an apocalyptic number.

20130402232131 is a deficient number, since it is larger than the sum of its proper divisors (6710134077381).

20130402232131 is an equidigital number, since it uses as much as digits as its factorization.

20130402232131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6710134077380.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 20130402232131 its reverse (13123220403102), we get a palindrome (33253622635233).

The spelling of 20130402232131 in words is "twenty trillion, one hundred thirty billion, four hundred two million, two hundred thirty-two thousand, one hundred thirty-one".

Divisors: 1 3 6710134077377 20130402232131