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20131030011120 = 2435711982755959
BaseRepresentation
bin1001001001111000111101…
…11001001000110011110000
32122021111201002112201220120
410210330132321020303300
510114311322140323440
6110452022330010240
74145263455523050
oct444743671106360
978244632481816
1020131030011120
116461581698826
122311641276980
13b3046a6a27b2
144d84c0447560
1524d9c3357dd0
hex124f1ee48cf0

20131030011120 has 80 divisors (see below), whose sum is σ = 71321363473920. Its totient is φ = 4601378287872.

The previous prime is 20131030011049. The next prime is 20131030011121. The reversal of 20131030011120 is 2111003013102.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×201310300111202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 20131030011120.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20131030011121) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5991376300 + ... + 5991379659.

It is an arithmetic number, because the mean of its divisors is an integer number (891517043424).

Almost surely, 220131030011120 is an apocalyptic number.

20131030011120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

20131030011120 is an abundant number, since it is smaller than the sum of its proper divisors (51190333462800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20131030011120 is a wasteful number, since it uses less digits than its factorization.

20131030011120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11982755982 (or 11982755976 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 20131030011120 its reverse (2111003013102), we get a palindrome (22242033024222).

The spelling of 20131030011120 in words is "twenty trillion, one hundred thirty-one billion, thirty million, eleven thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 7 8 10 12 14 15 16 20 21 24 28 30 35 40 42 48 56 60 70 80 84 105 112 120 140 168 210 240 280 336 420 560 840 1680 11982755959 23965511918 35948267877 47931023836 59913779795 71896535754 83879291713 95862047672 119827559590 143793071508 167758583426 179741339385 191724095344 239655119180 251637875139 287586143016 335517166852 359482678770 419396458565 479310238360 503275750278 575172286032 671034333704 718965357540 838792917130 958620476720 1006551500556 1258189375695 1342068667408 1437930715080 1677585834260 2013103001112 2516378751390 2875861430160 3355171668520 4026206002224 5032757502780 6710343337040 10065515005560 20131030011120