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2013310011331 is a prime number
BaseRepresentation
bin11101010011000010101…
…000001100011111000011
321010110201000222111000201
4131103002220030133003
5230441224330330311
64140522444430031
7265312461506563
oct35230250143703
97113630874021
102013310011331
11706927018353
12286239548317
13117b14c2a918
146d632476da3
15375867699c1
hex1d4c2a0c7c3

2013310011331 has 2 divisors, whose sum is σ = 2013310011332. Its totient is φ = 2013310011330.

The previous prime is 2013310011319. The next prime is 2013310011337. The reversal of 2013310011331 is 1331100133102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2013310011331 - 211 = 2013310009283 is a prime.

It is a super-3 number, since 3×20133100113313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 2013310011299 and 2013310011308.

It is not a weakly prime, because it can be changed into another prime (2013310011337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006655005665 + 1006655005666.

It is an arithmetic number, because the mean of its divisors is an integer number (1006655005666).

Almost surely, 22013310011331 is an apocalyptic number.

2013310011331 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013310011331 is an equidigital number, since it uses as much as digits as its factorization.

2013310011331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 2013310011331 its reverse (1331100133102), we get a palindrome (3344410144433).

The spelling of 2013310011331 in words is "two trillion, thirteen billion, three hundred ten million, eleven thousand, three hundred thirty-one".