Base | Representation |
---|---|
bin | 1011101110000011001… |
… | …1111101011100001001 |
3 | 201020200202010120002222 |
4 | 2323200303331130021 |
5 | 11244321043304001 |
6 | 232254443303425 |
7 | 20355253400354 |
oct | 2734063753411 |
9 | 636622116088 |
10 | 201340213001 |
11 | 7842a335054 |
12 | 3303051ab75 |
13 | 15ca8b96915 |
14 | 9a600ad29b |
15 | 5385e5961b |
hex | 2ee0cfd709 |
201340213001 has 2 divisors, whose sum is σ = 201340213002. Its totient is φ = 201340213000.
The previous prime is 201340212991. The next prime is 201340213037. The reversal of 201340213001 is 100312043102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 182158240000 + 19181973001 = 426800^2 + 138499^2 .
It is a cyclic number.
It is not a de Polignac number, because 201340213001 - 230 = 200266471177 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (201340219001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670106500 + 100670106501.
It is an arithmetic number, because the mean of its divisors is an integer number (100670106501).
Almost surely, 2201340213001 is an apocalyptic number.
It is an amenable number.
201340213001 is a deficient number, since it is larger than the sum of its proper divisors (1).
201340213001 is an equidigital number, since it uses as much as digits as its factorization.
201340213001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 201340213001 its reverse (100312043102), we get a palindrome (301652256103).
The spelling of 201340213001 in words is "two hundred one billion, three hundred forty million, two hundred thirteen thousand, one".
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