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201342341311 = 547936748009
BaseRepresentation
bin1011101110000011110…
…0000101000010111111
3201020200220010200121021
42323200330011002333
511244322114410221
6232255001045011
720355310443346
oct2734074050277
9636626120537
10201342341311
1178430559091
1233031186767
1315ca9460587
149a604a4b5d
15538622a041
hex2ee0f050bf

201342341311 has 4 divisors (see below), whose sum is σ = 201379094800. Its totient is φ = 201305587824.

The previous prime is 201342341273. The next prime is 201342341351. The reversal of 201342341311 is 113143243102.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 113143243102 = 256571621551.

It is a cyclic number.

It is not a de Polignac number, because 201342341311 - 29 = 201342340799 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201342341351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18368526 + ... + 18379483.

It is an arithmetic number, because the mean of its divisors is an integer number (50344773700).

Almost surely, 2201342341311 is an apocalyptic number.

201342341311 is a deficient number, since it is larger than the sum of its proper divisors (36753489).

201342341311 is an equidigital number, since it uses as much as digits as its factorization.

201342341311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36753488.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 201342341311 its reverse (113143243102), we get a palindrome (314485584413).

The spelling of 201342341311 in words is "two hundred one billion, three hundred forty-two million, three hundred forty-one thousand, three hundred eleven".

Divisors: 1 5479 36748009 201342341311