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BaseRepresentation
bin100111010101111
31000122001
410322233
51121033
6233131
7112504
oct47257
930561
1020143
1114152
12b7a7
139226
1474ab
155e7d
hex4eaf

20143 has 2 divisors, whose sum is σ = 20144. Its totient is φ = 20142.

The previous prime is 20129. The next prime is 20147. The reversal of 20143 is 34102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10071 + 10072.

It is an arithmetic number, because the mean of its divisors is an integer number (10072).

220143 is an apocalyptic number.

20143 is a deficient number, since it is larger than the sum of its proper divisors (1).

20143 is an equidigital number, since it uses as much as digits as its factorization.

20143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 10.

The square root of 20143 is about 141.9260370757. The cubic root of 20143 is about 27.2087162089.

Adding to 20143 its reverse (34102), we get a palindrome (54245).

The spelling of 20143 in words is "twenty thousand, one hundred forty-three", and thus it is an iban number.