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20153 = 72879
BaseRepresentation
bin100111010111001
31000122102
410322321
51121103
6233145
7112520
oct47271
930572
1020153
1114161
12b7b5
139233
1474b7
155e88
hex4eb9

20153 has 4 divisors (see below), whose sum is σ = 23040. Its totient is φ = 17268.

The previous prime is 20149. The next prime is 20161. The reversal of 20153 is 35102.

20153 is nontrivially palindromic in base 2.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35102 = 217551.

It is a cyclic number.

It is not a de Polignac number, because 20153 - 22 = 20149 is a prime.

It is a super-2 number, since 2×201532 = 812286818, which contains 22 as substring.

It is a Duffinian number.

It is an inconsummate number, since it does not exist a number n which divided by its sum of digits gives 20153.

It is not an unprimeable number, because it can be changed into a prime (20113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1433 + ... + 1446.

It is an arithmetic number, because the mean of its divisors is an integer number (5760).

220153 is an apocalyptic number.

It is an amenable number.

20153 is a deficient number, since it is larger than the sum of its proper divisors (2887).

20153 is an equidigital number, since it uses as much as digits as its factorization.

20153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2886.

The product of its (nonzero) digits is 30, while the sum is 11.

The square root of 20153 is about 141.9612623218. The cubic root of 20153 is about 27.2132180565.

Adding to 20153 its sum of digits (11), we get a square (20164 = 1422).

Adding to 20153 its reverse (35102), we get a palindrome (55255).

The spelling of 20153 in words is "twenty thousand, one hundred fifty-three".

Divisors: 1 7 2879 20153