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202113400103 = 659306697117
BaseRepresentation
bin1011110000111011100…
…1011011110100100111
3201022200122000112102022
42330032321123310213
511302412012300403
6232503303333355
720413362361226
oct2741671336447
9638618015368
10202113400103
1178796821a5a
123320745125b
13160a011c394
149ad4a58cbd
1553cdc86d38
hex2f0ee5bd27

202113400103 has 4 divisors (see below), whose sum is σ = 202420097880. Its totient is φ = 201806702328.

The previous prime is 202113400079. The next prime is 202113400109. The reversal of 202113400103 is 301004311202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 202113400103 - 28 = 202113399847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202113400109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153347900 + ... + 153349217.

It is an arithmetic number, because the mean of its divisors is an integer number (50605024470).

Almost surely, 2202113400103 is an apocalyptic number.

202113400103 is a deficient number, since it is larger than the sum of its proper divisors (306697777).

202113400103 is an equidigital number, since it uses as much as digits as its factorization.

202113400103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 306697776.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 202113400103 its reverse (301004311202), we get a palindrome (503117711305).

The spelling of 202113400103 in words is "two hundred two billion, one hundred thirteen million, four hundred thousand, one hundred three".

Divisors: 1 659 306697117 202113400103